STPM MT Archives - Page 15 of 61

Geometric Progression I

Feb 5 | Random Question

Geometric Progression I

STPM 2015 MT Chapter 8 Booklet B Page 35 Problem 17

Jan 30 | KK LEE Booklet Solution

June 2014/1

STPM 2014 Term 3 Reward

Jan 27 | Announcement, STPM Tuition

RM50 per subject are rewarded for Ai Tuition students who obtained (GPA) of more than 3.0 of the subject in STPM term 3 examination (i.e. B+, A-, A).

STPM 2014 Term 3 Result Day

Jan 25 | STPM Exam

STPM 2014 Term 3 Result Day

Federal Territory Day

Jan 21 | Announcement

Mathematics (T) class at Ai Tuition Centre (Kuala Lumpur) on Sunday 1st February 2015 are cancelled due to Federal Territory Day.

Pelangi Differentiation Exercise 2.15

Jan 20 | Textbook Solution

An inverted right circular cone of semi-vertical angle...

Polynomial Question from student I

Jan 14 | Random Question

Solve the equation $r^6-4.2r^4+3.2=0$ .

STPM 2015 MT Chapter 8 Booklet A Page 20 Problem 11 Question 2

Jan 4 | KK LEE Booklet Solution

Given that $y=\sqrt{\cos{x}}$ , show that $4y^3\frac{d^2y}{dx^2}+y^4+1=$ 0.

Integration question from student I

Dec 31 | Random Question

Random question which was asked by a lovely student.

STPM 2015 MT Chapter 8 Booklet A Page 20 Problem 11 Question 14

Dec 29 | KK LEE Booklet Solution

Given that $y=\sec^{-1}(e^x)$ , prove that $\frac{dy}{dx}=\frac{1}{\sqrt{e^{2x}-1}}$ .

2015 MT Chapter 8 Booklet A Page 20 Problem 11 Question 11

Dec 27 | KK LEE Booklet Solution

Given that $y=(\sin^{-1}x)^2$ , show that $(1-x^2)\frac{d^2y}{dx^2}-x\frac{dy}{dx}-2=$ 0.

STPM 2013 Mathematics (T) and (M) Final Grade

Dec 27 | STPM Reference

This is the collection of the final grade of the new STPM Mathematics (T) year 2013. The final grade of Mathematics...

2015 MT Chapter 8 Booklet A Page 20 Question 6

Dec 26 | KK LEE Booklet Solution

Given that $y=\ln(1+x)-x+\frac{1}{2}x^2$ show that $\frac{dy}{dx}>=0$ for all values of $x>-1$ .

2015 MT Chapter 8 Booklet A Page 20 Question 10

Dec 26 | KK LEE Booklet Solution

If $\sin y = 2 \sin x$ , show that (a) $(\frac{dy}{dx})^2=1+3\sec^2 y$ , (b) by differentiating (a) with respect to $x$ , show that $\frac{d^2y}{dx^2}=3\sec^2 y \tan y$ , and hence that $\cot y \frac{d^2y}{dx^2}-(\frac{dy}{dx})^2+1=$ $0$ .

2015 MT Chapter 8 Booklet A Page 20 Question 8

Dec 24 | KK LEE Booklet Solution

Given $y=\ln(\sin px + \cos px)$ . Prove that $\frac{d^2y}{dx^2}+(\frac{dy}{dx})^2+p^2=0$ .

Free STPM Mathematics Term 1 Intensive Workshop

Oct 3 | STPM Tuition, Tuition

Last Preparation for Term 3 Examination
(For October Maths Students)
6 Hours of Term 2 Intensive Workshop

Free STPM Mathematics Term 3 Intensive Workshop

Oct 3 | STPM Tuition, Tuition

Last Preparation for Term 3 Examination
(For October Maths Students)
4 Hours of Term 3 Intensive Workshop

Complex Number Problem 1

Oct 3 | KK LEE Booklet Solution

...

Pelangi MT Chapter 6 Revision Exercise Q17

Oct 2 | Textbook Solution

The position vectors of point and relative to...

MT Chapter 15 Booklet Page 23 Question 2

Sep 4 | KK LEE Booklet Solution

Here are our...

0182016992

kklee@kkleemaths.com

TAG ARCHIVE

Geometric Progression I

STPM 2015 MT Chapter 8 Booklet B Page 35 Problem 17

STPM 2014 Term 3 Reward

STPM 2014 Term 3 Result Day

Federal Territory Day

Pelangi Differentiation Exercise 2.15

Polynomial Question from student I

STPM 2015 MT Chapter 8 Booklet A Page 20 Problem 11 Question 2

Integration question from student I

STPM 2015 MT Chapter 8 Booklet A Page 20 Problem 11 Question 14

2015 MT Chapter 8 Booklet A Page 20 Problem 11 Question 11

STPM 2013 Mathematics (T) and (M) Final Grade

2015 MT Chapter 8 Booklet A Page 20 Question 6

2015 MT Chapter 8 Booklet A Page 20 Question 10

2015 MT Chapter 8 Booklet A Page 20 Question 8

Free STPM Mathematics Term 1 Intensive Workshop

Free STPM Mathematics Term 3 Intensive Workshop

Complex Number Problem 1

Pelangi MT Chapter 6 Revision Exercise Q17

MT Chapter 15 Booklet Page 23 Question 2

018-2016992

kklee@kkleemaths.com

Subscribe to Newsletter

Success!

+60 18 2016992

kklee@kkleemaths.com